# How to solve long equations The following steps provide a good method to use when solving linear equations.

1. Simplify each side of the equation by removing parentheses and combining like terms.
2. Use addition or subtraction to isolate the variable term on one side of the equation.
3. Use multiplication or division to solve for the variable.

Note: Fractions may be removed by multiplying each side of the equation by the common denominator.

Example:

Solve for z: 7z – (3z – 4) = 12

Solution:

Step 1. Simplify the left side of the equation by removing parentheses and combining like terms.

Distribute through by -1.

7z 3z+ 4 = 12

Combine like terms on the left side of the equation.

4z + 4 = 12

Step 2. Use subtraction to isolate the variable term on the left side of the equation.

Subtract 4 from each side of the equation.

4z + 4 – 4 = 12 – 4

4z = 8

Step 3. Use division to solve for the variable.

Divide each side of the equation by 4. The solution to 7z – (3z – 4) = 12 is z = 2.

Solve for y: (y - 11) - (y + 8) = 6y

Solve for x: 0.8(5x + 15) = 2.6 - (x + 3)

Sours: https://sites.austincc.edu/tsiprep/math-review/equations/a-general-rule-for-solving-equations/

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## Solving Equations

### What is an Equation?

An equation says that two things are equal. It will have an equals sign "=" like this:

That equations says: what is on the left (x − 2) is equal to what is on the right (4)

So an equation is like a statement "this equals that"

### What is a Solution?

A Solution is a value we can put in place of a variable (such as x) that makes the equation true.

### Example: x − 2 = 4

When we put 6 in place of x we get:

6 − 2 = 4

which is true

So x = 6 is a solution.

How about other values for x ?

• For x=5 we get "5−2=4" which is not true, so x=5 is not a solution.
• For x=9 we get "9−2=4" which is not true, so x=9 is not a solution.
• etc

In this case x = 6 is the only solution.

You might like to practice solving some animated equations.

### More Than One Solution

There can be more than one solution.

### Example: (x−3)(x−2) = 0

When x is 3 we get:

(3−3)(3−2) = 0 × 1 = 0

which is true

And when x is 2 we get:

(2−3)(2−2) = (−1) × 0 = 0

which is also true

So the solutions are:

x = 3, or x = 2

When we gather all solutions together it is called a Solution Set

The above solution set is: {2, 3}

### Solutions Everywhere!

Some equations are true for all allowed values and are then called Identities

### Example: sin(−θ) = −sin(θ) is one of the Trigonometric Identities

Let's try θ = 30°:

sin(−30°) = −0.5 and

−sin(30°) = −0.5

So it is true for θ = 30°

Let's try θ = 90°:

sin(−90°) = −1 and

−sin(90°) = −1

So it is also true for θ = 90°

Is it true for all values of θ? Try some values for yourself!

### How to Solve an Equation

There is no "one perfect way" to solve all equations.

### A Useful Goal

But we often get success when our goal is to end up with:

In other words, we want to move everything except "x" (or whatever name the variable has) over to the right hand side.

### Example: Solve 3x−6 = 9

Add 6 to both sides:3x = 9+6

Divide by 3:x = (9+6)/3

Now we have x = something,

and a short calculation reveals that x = 5

### Like a Puzzle

In fact, solving an equation is just like solving a puzzle. And like puzzles, there are things we can (and cannot) do.

Here are some things we can do:

### Example: Solve √(x/2) = 3

Square both sides:x/2= 32

Calculate 32 = 9:x/2 = 9

Multiply both sides by 2:x = 18

And the more "tricks" and techniques you learn the better you will get.

### Special Equations

There are special ways of solving some types of equations. Learn how to ...

You should always check that your "solution" really is a solution.

### How To Check

Take the solution(s) and put them in the original equation to see if they really work.

### Example: solve for x:

2xx − 3 + 3 = 6x − 3     (x≠3)

We have said x≠3 to avoid a division by zero.

Let's multiply through by (x − 3):

2x + 3(x−3) = 6

Bring the 6 to the left:

2x + 3(x−3) − 6 = 0

Expand and solve:

2x + 3x − 9 − 6 = 0

5x − 15 = 0

5(x − 3) = 0

x − 3 = 0

That can be solved by having x=3

Let us check:

2 × 33 − 3 + 3  =  63 − 3

Hang On!
That means Dividing by Zero!

And anyway, we said at the top that x≠3, so ...

x = 3 does not actually work, and so:

There is No Solution!

That was interesting ... we thought we had found a solution, but when we looked back at the question we found it wasn't allowed!

This gives us a moral lesson:

"Solving" only gives us possible solutions, they need to be checked!

### Tips

• Note down where an expression is not defined (due to a division by zero, the square root of a negative number, or some other reason)
• Show all the steps, so it can be checked later (by you or someone else)

Algebra - Basic DefinitionsAlgebra Index

Sours: https://www.mathsisfun.com/algebra/equations-solving.html
Strategies to Solve Multi Step Linear Equations with Fractions

Solving Multi-Step Equations

Learning Objective(s)

·         Use properties of equality together to isolate variables and solve algebraic equations.

·         Use the properties of equality and the distributive property to solve equations containing parentheses, fractions, and/or decimals.

There are some equations that you can solve in your head quickly. For example – what is the value of y in the equation 2y = 6? Chances are you didn’t need to get out a pencil and paper to calculate that y = 3. You only needed to do one thing to get the answer, divide 6 by 2.

Other equations are more complicated. Solving without writing anything down is difficult! That’s because this equation contains not just a variable but also fractions and terms inside parentheses. This is a multi-step equation, one that takes several steps to solve. Although multi-step equations take more time and more operations, they can still be simplified and solved by applying basic algebraic rules.

Using Properties of Equalities

Remember that you can think of an equation as a balance scale, with the goal being to rewrite the equation so that it is easier to solve but still balanced. The addition property of equality and the multiplication property of equality explain how you can keep the scale, or the equation, balanced. Whenever you perform an operation to one side of the equation, if you perform the same exact operation to the other side, you’ll keep both sides of the equation equal.

If the equation is in the form, ax + b = c, where x is the variable, you can solve the equation as before. First “undo” the addition and subtraction, and then “undo” the multiplication and division.

 Example Problem Solve 3y + 2 = 11. Subtract 2 from both sides of the equation to get the term with the variable by itself.  Divide both sides of the equation by 3 to get a coefficient of 1 for the variable. Answer y = 3

 Example Problem Solve . Add 2 from to both sides of the equation to get the term with the variable by itself.    Multiply both sides of the equation by 4 to get a coefficient of 1 for the variable. Answer x = 20

If the equation is not in the form, ax + b = c, you will need to perform some additional steps to get the equation in that form.

In the example below, there are several sets of like terms. You must first combine all like terms.

 Example Problem Solve 3x + 5x + 4 – x + 7 = 88. There are three like terms 3x, 5x and –x involving a variable. Combine these like terms.4 and 7 are also like terms and can be added.The equation is now in the form ax + b = c. So, we can solve as before.   Subtract 11 from both sides. Divide both sides by 7. Answer x = 11

Some equations may have the variable on both sides of the equal sign. We need to “move” one of the variable terms in order to solve the equation.

 Example Problem Solve 6x + 5 = 10 + 5x. Check your solution. This equation has x terms on both the left and the right. To solve an equation like this, you must first get the variables on the same side of the equal sign. You can subtract 5x on each side of the equal sign, which gives a new equation: x + 5 = 10. This is now a one-step equation!  Subtract 5 from both sides. Check Check your solution by substituting 5 for x in the original equation. This is a true statement, so the solution is correct. Answer x = 5

Here are some steps to follow when you solve multi-step equations.

 Solving multi-step equations 1.  If necessary, simplify the expressions on each side of the equation, including combining like terms.2. Get all variable terms on one side and all numbers on the other side using the addition property of equality. (ax + b = c or c = ax + b)3. Isolate the variable term using the inverse operation or additive inverse (opposite) using the addition property of equality.4.  Isolate the variable using the inverse operation or multiplicative inverse (reciprocal) using the multiplication property of equality to write the variable with a coefficient of 1.5. Check your solution by substituting the value of the variable in the original equation.

The examples below illustrate this sequence of steps.

 Example Problem Solve for y.-20y  + 15 = 2 - 16y + 11 Step 1. On the right side, combine like terms: 2 + 11 = 13.  Step 2. Add 20y to both sides to remove the variable term from the left side of the equation. Step 3. Subtract 13 from both sides.  Step 4. Divide 4y by 4 to solve for y. Check Step 5. To check your answer, substitute for y in the original equation. The statement 5 = 5 is true, so y = is the solution. Answer Advanced Example Problem Solve 3y + 10.5 = 6.5 + 2.5y. Check your solution. This equation has y terms on both the left and the right. To solve an equation like this, you must first get the variables on the same side of the equal sign. Add -2.5y to both sides so that the variable remains on one side only. Now isolate the variable by subtracting 10.5 from both sides. Multiply both sides by 10 so that 0.5y becomes 5y, then divide by 5. Check Check your solution by substituting -8 in for y in the original equation.This is a true statement, so the solution is correct. Answer y = -8

 Advanced QuestionIdentify the step that will not lead to a correct solution to the problem. A) Multiply both sides of the equation by 2.B) Add to both sides of the equation.C) Add to the left side, and add to the right side.D) Rewrite as .

Solving Equations Involving Parentheses, Fractions, and Decimals

More complex multi-step equations may involve additional symbols such as parentheses. The steps above can still be used. If there are parentheses, you use the distributive property of multiplication as part of Step 1 to simplify the expression. Then you solve as before.

 The Distributive Property of Multiplication For all real numbers a, b, and c, a(b + c) = ab + ac.

What this means is that when a number multiplies an expression inside parentheses, you can distribute the multiplication to each term of the expression individually. Then, you can follow the routine steps described above to isolate the variable to solve the equation.

 Example Problem Solve for a.4(2a + 3) =  −3(a− 1) + 31 Apply the distributive property to expand 4(2a + 3) to 8a + 12 and −3(a – 1) to −3a + 3. Combine like terms. Add 3a to both sides to move the variable terms to one side. Subtract 12 to isolate the variable term. Divide both terms by 11 to get a coefficient of 1. Answer a = 2

 In which of the following equations is the distributive property properly applied to the equation 2(y +3) = 7? A) y + 6 = 7B) 2y + 6 = 14C) 2y + 6 = 7D) 2y + 3 = 7 Show/Hide AnswerA) y + 6 = 7Incorrect. All of the terms inside the parentheses must be multiplied by the value outside. The correct answer is 2y + 6 = 7. B) 2y + 6 = 14Incorrect. When applying the distributive property, multiplication is spread only to the terms inside the parentheses, not to the other parts of the equation. The correct answer is 2y + 6 = 7. C) 2y + 6 = 7Correct. Since the distributive property allows us to distribute the multiplication of an entire expression to each of the terms of the expression separately, 2y + 6 = 7 is correct. D) 2y + 3 = 7Incorrect. All of the terms inside the parentheses must be multiplied by the value outside. The correct answer is 2y + 6 = 7.

If you prefer not working with fractions, you can use the multiplication property of equality to multiply both sides of the equation by a common denominator of all of the fractions in the equation. See the example below.

 Example Problem Solve by clearing the fractions in the equation first. Multiply both sides of the equation by 4, the common denominator of the fractional coefficients.  Use the distributive property to expand the expressions on both sides.  Multiply. Add 3x to both sides to move the variable terms to only one side.Add 12 to both sides to move the constant terms to the other side. Divide to isolate the variable. Answer Of course, if you like to work with fractions, you can just apply your knowledge of operations with fractions and solve.

 Example Problem Solve . Add to both sides to get the variable terms on one side.  Add 3 to both sides to get the constant terms on the other side.   To get a coefficient of 1, multiply the variable term by its multiplicative inverse. Answer Advanced Example Problem Solve . Check your solution. Solving this equation will require multiple steps. Begin by evaluating 32 = 9. Now distribute the on the left side of the equation. Multiply both sides of the equation by 18, the common denominator of the fractions in the problem.Use the distributive property to expand the expression on the left side. Then remove a factor of 1 from both sides. On the left, you can think of . On the right, you can think of . Continue solving for a using the distributive property.    Then isolate the variable, and solve the remaining one-step problem. Check Check your solution by substituting in for a in the original equation.                             This is a true statement, so the solution is correct. Answer To clear the fractions from , we can multiply both sides of the equation by which of the following numbers? 3   6   9   27 A) 9B) 9 or 27C) 6D) 3 or 9 Show/Hide AnswerA) 9Incorrect. While 9 is a common denominator of and , so is 27. Any denominator will work, not just the least one. The correct answer is 9 and 27. B) 9 or 27Correct. Both 9 and 27 are common denominators of and . C) 6Incorrect. You clear fractions by multiplying them by a common denominator. 6 is not a common denominator of and . The correct answer is 9 and 27. D) 3 or 9Incorrect. While 9 is a common denominator of and , 3 is not. The correct answer is 9 and 27.

Regardless of which method you use to solve equations containing variables, you will get the same answer. You can choose the method you find easier! Remember to check your answer by substituting your solution into the original equation.

Just as you can clear fractions from an equation, you can clear decimals from the equation in the same way. Find a common denominator and use the multiplication property of equality to multiply both sides of the equation.

 Example Problem Solve 0.4x – 0.25 = 1.75 by clearing the decimals first. 0.4 ( ) and 0.25 ( ) and 1.75 ( ) have a common denominator of 100. Multiply both sides by 100.  Apply the distributive property to clear the parentheses.Solve as before. Add 25 to both sides. Divide both sides by 40. Check: Substitute x = 5 into the original equation.  Evaluate.The solution checks. Answer Advanced QuestionSolve for a: A) a = 2B) a = 1C) a = 0D) a = -2 Show/Hide AnswerA) a = 2Incorrect. Try multiplying both sides of the equation by 4, as . The new equation will be , which reduces to . The correct answer is: a = 1. B) a = 1Correct. You can solve this equation by multiplying both sides by 4, since . The resulting equation, can be rewritten as , and then . You find that a = 1. C) a = 0Incorrect.  Substituting a = 0 into the equation, you find , so . This is not accurate. The correct answer is: a = 1. D) a = -2Incorrect. Try multiplying both sides of the equation by 4, as . The new equation will be , which reduces to . The correct answer is: a = 1.

Complex, multi-step equations often require multi-step solutions. Before you can begin to isolate a variable, you may need to simplify the equation first. This may mean using the distributive property to remove parentheses, or multiplying both sides of an equation by a common denominator to get rid of fractions. Sometimes it requires both techniques. Sours: http://www.montereyinstitute.org/courses/DevelopmentalMath/COURSE_TEXT2_RESOURCE/U10_L1_T2_text_final.html

## Solve how equations to long

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Solving a multi step equation

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